-t^2=16-8t

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Solution for -t^2=16-8t equation: 



-t^2=16-8t

We move all terms to the left:

-t^2-(16-8t)=0

We add all the numbers together, and all the variables

-t^2-(-8t+16)=0

We add all the numbers together, and all the variables

-1t^2-(-8t+16)=0

We get rid of parentheses

-1t^2+8t-16=0

a = -1; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-8}{-2}=+4$

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